If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12v^2+31v+12=0
a = 12; b = 31; c = +12;
Δ = b2-4ac
Δ = 312-4·12·12
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{385}}{2*12}=\frac{-31-\sqrt{385}}{24} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{385}}{2*12}=\frac{-31+\sqrt{385}}{24} $
| 5=2x+4x+8x-9 | | -92+4x=76+10x | | (10x+8)+(10x+2)=90 | | -2x-2(2x-10)=55 | | 23+1.50m=29+0.75m | | 3s=8.58 | | c=12(2)(3.14) | | x-5/x+1=2/3 | | 0.8=3/x | | 14-h-2h=-7 | | 14x+17=x-4 | | n2+ 2=4 | | 14+6b+7-2b=1-5b | | (13x+8)+(27x+2)=90 | | x-4/3=13 | | x3−7=23 | | 2(−5x+4)+4x−5=-3 | | 5x*5x*3x-8*3x-8=848 | | 12x-26=180 | | x+8/5=x-1/2 | | 3(x+9)–(5x-2)=14 | | -3=-6/5(x+1) | | 6(5+2x)-5x=72 | | 4x-9+2x+3=90 | | (3x+38)=(4x+39) | | 40=y/4 | | 1/2(4b+8)-12=-36 | | 5x-100=-85 | | x=21=19 | | 2x+4x=36–12 | | x+3/x−1=4/5 | | 6(y-1)=9,4-1,7y |